Romney captures all 77 counties in Oklahoma
Mitt Romney, the Republican presidential candidate, wins Oklahoma and leads in all counties reporting results. GOP nominees have captured all 77 Oklahoma counties in last two presidential races and topped 65 percent of the vote.
WASHINGTON — Mitt Romney continued a long streak of Republican presidential wins in Oklahoma on Tuesday and gave the GOP its third straight sweep of the state’s 77 counties.
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With most of the precincts reporting, Romney had 67 percent of the vote and President Barack Obama had 33 percent, slightly less than he won in 2008. Romney’s win in the state gave him seven electoral votes, but Obama’s supporters in the state claimed the ultimate victory as the president won a second term.
It was unclear late Tuesday whether Romney would have his best margin in Oklahoma, as Republican John McCain did in 2008.
With 71 percent of the vote counted in Wyoming, Romney had 69 percent in that western state.
Obama topped 40 percent in just a few Oklahoma counties, including Oklahoma County, where he got 41 percent.
The Republican presidential candidate also won every county in Oklahoma in the 2004 and 2008 presidential elections and topped 65 percent of the vote in each.
In 2008, Oklahoma gave Republican presidential candidate John McCain his best percentage in the country — 65.65 percent.
Romney wasn’t the first choice of Oklahoma Republicans in the March presidential primary; he finished second to former Sen. Rick Santorum.
But Oklahomans contributed $4.2 million to Romney’s campaign, compared with $1.8 million to Obama’s.
A Democratic presidential nominee hasn’t captured Oklahoma since then-President Lyndon B. Johnson in 1964.
Democrat Franklin D. Roosevelt was the first to win all 77 counties in Oklahoma; he did that in 1932 and won 73 percent of the vote.
Then-President Richard Nixon, a Republican, also won every county in 1972.
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